Calculate the mass of the precipitate that forms when barium nitrate and potassium sulfate react. The mass of barium nitrate is 280g.
| November 30, 2020 | education
ba (no3) 2 + k2so4 = baso4 + 2kno3
find the amount of substance
n (ba (no3) 2) = 280/261 = 1.07 mol
the amount of substance in barium nitrate and barium sulfate is the same therefore
n (baso4) = 1.07 mol
from here we find the mass of sediment
m (baso4) = 1.07 * 233 = 249.31g
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