Calculate the mass of the precipitate that forms when calcium hydroxide reacts with 200 g of 5%

The reaction of interaction of calcium hydroxide with potassium carbonate is described by the following chemical reaction equation:

Ca (OH) 2 + K2CO3 = CaCO3 + 2KOH;

From 1 mol of calcium hydroxide, 1 mol of calcium carbonate is synthesized.

Let’s calculate the available chemical amount of calcium hydroxide substance.

M Ca (OH) 2 = 40 + 16 x 2 + 1 x 2 = 74 grams / mol;

N Ca (OH) 2 = 200 x 0.05 / 74 = 0.135 mol;

During the reaction, the same amount of calcium carbonate will be synthesized.

Let’s calculate the weight of calcium carbonate. To do this, we multiply the amount of the substance by its molar weight.

M CaCO3 = 40 + 12 + 16 x 3 = 100 grams / mol;

m CaCO3 = 0.135 x 100 = 13.5 grams;