Calculate the mass of the precipitate that forms when potassium carbonate interacts

| September 5, 2021 | education

Calculate the mass of the precipitate that forms when potassium carbonate interacts with a solution of barium nitrate weighing 150 g and a mass fraction of 2%.

1. The interaction of potassium carbonate with barium nitrate is described by the equation:

K2CO3 + Ba (NO3) 2 = BaCO3 ↓ + 2KNO3.

2. Determine the mass of barium nitrate:

m (Ba (NO3) 2) = w (Ba (NO3) 2) * m (solution) = 0.02 * 150 = 3 g.

3. Find the chemical amount of barium nitrate:

n (Ba (NO3) 2) = m (Ba (NO3) 2): M (Ba (NO3) 2);

M (Ba (NO3) 2) = 137 + 2 * 14 + 6 * 16 = 261 g / mol;

n (Ba (NO3) 2) = 3: 261 = 0.0115 mol.

4. Set the amount of barium carbonate:

n (BaCO3) = n (Ba (NO3) 2) = 0.0115 mol.

5. Let’s calculate the mass of the sediment:

m (BaCO3) = n (BaCO3) * M (BaCO3);

M (BaCO3) = 137 + 12 + 3 * 16 = 197 g / mol;

m (BaCO3) = 0.0115 * 197 = 2.2655 g.

Answer: 2.2655 g.



One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.