Calculate the mass of the precipitate that forms when sulfuric acid interacts with 300 g of a 15% barium chloride solution

The reaction between sulfuric acid and barium chloride is described by the following chemical reaction equation:

BaCl2 + H2SO4 = BaSO4 + 2HCl;

In the interaction of 1 mol of barium chloride and 1 mol of sulfuric acid, 1 mol of insoluble barium sulfate is synthesized.

Let’s calculate the chemical amount of a substance that is contained in 300 grams of a 15% barium chloride solution.

M BaCl2 = 137 + 35.5 x 2 = 208 grams / mol;

N BaCl2 = 300 x 0.15 / 208 = 0.216 mol;

The same amount of barium sulfate will be synthesized.

Let’s calculate its weight.

M BaSO4 = 137 + 32 + 16 x 4 = 233 grams / mol;

m BaSO4 = 233 x 0.216 = 50.328 grams;