Calculate the mass of the precipitate that forms when two solutions react

| July 17, 2021 | education

Calculate the mass of the precipitate that forms when two solutions react, the first containing 21.2 g of sodium carbonate, and the second calcium chloride.

Let’s write the reaction equation:
Na2Co3 + CaCl2 = 2NaCl + CaCO3 ↓.
It can be seen from the reaction equation that:
ν (Na2Co3) = ν (CaCO3).
Knowing that ν (in-va) = m (in-va) / M (in-va) = V (in-va) / Vm (in-va), we get:
m (Na2Co3) / M (Na2Co3) = m (CaCO3) / M (CaCO3).
Let’s define the molar masses:
M (Na2CO3) = 23 * 2 + 12 + 16 * 3 = 106 g / mol.
M (CaCO3) = 40 + 12 + 16 * 3 = 100 g / mol.
Determine the mass of the calcium carbonate sediment:
m (CaCO3) = m (Na2CO3) * M (CaCO3) / M (Na2Co3).
Substitute the numerical values:
m (CaCO3) = m (Na2CO3) * M (CaCO3) / M (Na2Co3) = 21.5 * 100/106 = 20.3 g.
Answer: The mass of calcium carbonate sediment is 20.3 g.



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