Calculate the mass of the precipitate that precipitated during the interaction of sulfuric

Calculate the mass of the precipitate that precipitated during the interaction of sulfuric acid with a solution containing 6.24 g of barium chloride.

When sulfuric acid interacts with barium chloride, a precipitate of insoluble salt – barium sulfate – precipitates. The reaction equation looks like this:

H2SO4 + BaCl2 = BaSO4 + 2 HCl

The molar mass of barium chloride is 207 g / mol; the molar mass of barium sulfate is 233 g / mol.

For the calculation, let’s make a proportion:

6.42 g of barium chloride corresponds to X g of barium sulfate, as

207 g / mol barium chloride corresponds to 233 g / mol barium sulfate.

X = (6.24 * 233) / 207 = 7 g of barium chloride

Answer: the mass of barium sulfate sediment is 7 grams.