Calculate the mass of the precipitate that precipitated when an excess of potassium carbonate (K2CO3)

| January 22, 2021 | education

Calculate the mass of the precipitate that precipitated when an excess of potassium carbonate (K2CO3) interacted with 170 g of barium nitrate solution (Ba (NO3) 2) with a mass fraction of the latter of 16%.

We draw up the reaction equation and place the coefficients: K2CO3 + Ba (NO3) 2 = 2KNO3 + BaCO3.
The precipitate is barium carbonate.
1) Find the mass of the solute barium nitrate. For this, we multiply the mass fraction of the substance by the mass of the solution and divide by one hundred percent: 170 * 16/100 = 27.2 g.
2) Molar mass of barium nitrate: 137 + 2 (14 + 48) = 261.
3) Find the amount of barium nitrate substance: 27.2 / 261 = 0.1 mol.
4) According to the reaction equation, there is one mole of barium carbonate for one mole of barium nitrate. This means that the amount of carbonate substance is 0.1 mol.
5) Sludge weight: 0.1 * 197 = 19.7 g – answer.



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