Calculate the mass of the precipitate that will precipitate when an excess of potassium carbonate interacts with 17.4 g

Calculate the mass of the precipitate that will precipitate when an excess of potassium carbonate interacts with 17.4 g of a solution of barium nitrate with a mass fraction of the latter of 15%.

The reaction of interaction of potassium carbonate with barium nitrate is described by the following chemical reaction equation:

Ba (NO3) 2 + K2CO3 = BaCO3 + 2KNO3;

When 1 mol of barium nitrate and 1 mol of sodium potassium carbonate interact, 1 mol of insoluble barium carbonate is synthesized.

Let’s calculate the chemical amount of a substance that is contained in 17.4 grams of a 15% barium nitrate solution.

M Ba (NO3) 2 = 137 + (14 + 16 x 3) x 2 = 261 grams / mol;

N Ba (NO3) 2 = 17.4 x 0.15 / 261 = 0.01 mol;

Thus, not more than 0.01 mol of barium carbonate will be synthesized.

Let’s calculate its weight.

M BaCO3 = 137 + 12 + 16 x 3 = 197 grams / mol;

m BaCO3 = 197 x 0.01 = 1.97 grams;