Calculate the mass of the precipitate that will result from the interaction of 0.1 mol of potassium hydroxide with copper chloride.

Let’s compose the reaction equation, find the quantitative ratios of substances.

2KOH + CuCl2 = Cu (OH) 2 ↓ + 2KCl.

According to the reaction equation, there is 1 mol of Cu (OH) 2 per 2 mol of KOH. Substances are in quantitative ratios of 2: 1.

The amount of Cu (OH) 2 will be 2 times less than KOH.

n (Cu (OH) 2) = ½ n (KOH) = 0.1: 2 = 0.05 mol.

Find the mass of Cu (OH) 2.

M (Cu (OH) 2) = 98 g / mol.

m = n × M.

m = 98 g / mol × 0.05 mol = 4.9 g.

Answer: 4.9 g.