Calculate the mass of the precipitate that will result from the interaction of 60 g of sodium

Calculate the mass of the precipitate that will result from the interaction of 60 g of sodium hydroxide (NaOH) with a mass fraction of 50% with an excess of NiSo4 solution.

Given:

m (NaOH) = 60 g

w% (NaOH) = 50%

To find:

m (draft) -?

Decision:

2NaOH + NiSO4 = Ni (OH) 2 + Na2SO4, – we solve the problem based on the composed reaction equation:

1) Find the mass of sodium hydroxide in the solution:

m (NaOH) = 60 g * 0.5 = 30 g

2) Find the amount of sodium hydroxide:

n (NaOH) = m: M = 30 g: 40 g / mol = 0.75 mol

3) We compose a logical expression:

if 2 mol NaOH gives 1 mol Ni (OH) 2,

then 0.75 mol NaOH will give x mol Ni (OH) 2,

then x = 0.375 mol.

4) Find the mass of precipitated nickel hydroxide:

m (Ni (OH) 2) = n * M = 0.375 mol * 92 g / mol = 34.5 g.

Answer: m (Ni (OH) 2) = 34.5 g.