Calculate the mass of the product formed during the combustion of 100 g of sulfur in an excess of oxygen?

1.Let’s find the amount of substance S:

M (S) = 32 g / mol.

n = 100 g: 32 g / mol = 3.125 mol.

Let’s find the quantitative ratios of substances.

S + O2 = SO2.

For 1 mole of S, there is 1 mole of SO2.

Substances are in quantitative ratios 1: 1.

The amount of substance is equal.

n (SO2) = n (S) = 3.125 mol.

Let’s find the mass of SO3.

M (SO2) = 64 g / mol.

m = n × M.

m = 64 g / mol × 3.125 mol = 200 g.

Answer: 200 g.