Calculate the mass of the product if chlorine has reacted with 10 g of technical magnesium, which contains 9% of impurities?

Given:
m (Mg) = 10g
w (impurities) = 9%
Calculate:
m (MgCl2) -?
1 mol 1 mol
Cl2 + Mg – MgCl2

M (Mg) = 24.3 g / mol
M (MgCl2) = 24.3 + 35.45 * 2 = 95.2 g / mol
m (Mg) pure = 10g * 91% = 9.1g
v (Mg) = 9.1g / 24.3g / mol = 0.37mol
The reaction equation shows: v (MgCl2) = v (Mg) = 0.37 mol
m (MgCl2) = 0.37 mol * 95.2 g / mol = 35.22 g



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