Calculate the mass of the product of the interaction of carbon dioxide with a volume of 22.4 liters

| June 3, 2021 | education

Calculate the mass of the product of the interaction of carbon dioxide with a volume of 22.4 liters. and calcium oxide by weight 58 g, which contains 3.5% of impurities by weight.

1. Let’s write down the reaction equation:

CaO + CO2 = CaCO3.

2. Find the chemical amount of calcium oxide and carbon dioxide (Vm – molar volume, constant equal to 22.4 l / mol):

n (CO2) = V (CO2) / Vm = 22.4 l / 22.4 l / mol = 1 mol.

ω (CaO) = 100% – ω (impurities) = 100% – 3.5% = 96.5%.

m (CaO) = m (solution) * ω (CaO) / 100% = 58 g * 96.5% / 100% = 55.97 g.

n (CaO) = m (CaO) / M (CaO) = 55.97 g / 56 g / mol = 1 mol.

3. Using the reaction equation, we find the chemical amount of salt:

n (CaCO3) = n (CaO) = 1 mol.

m (CaCO3) = n (CaCO3) * M (CaCO3) = 1 mol * 100 g / mol = 100 g.

Answer: m (CaCO3) = 100 g.



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