Calculate the mass of the reaction product if a solution of sulfuric acid with a mass of 160 g

Calculate the mass of the reaction product if a solution of sulfuric acid with a mass of 160 g with a mass fraction of 40% and an alkali solution of potassium hydroxide were taken to obtain it.

The reaction of potassium hydroxide and sulfuric acid solution to produce potassium sulfate.
2KOH + H2SO4 = K2SO4 + 2H2O.
Let’s determine the mass of sulfuric acid in solution.
m (H2SO4) = W (H2SO4) • m (solution) / 100% = 40% • 160 g / 100% = 64 g.
The number of moles of acid.
n (H2SO4) = m / Mr = 64 g / 98 g / mol = 0.65 mol.
The number of moles of potassium sulfate will correspond to the number of moles of acid.
n (H2SO4) = n (K2SO4) = 0.65 mol.
The mass of the salt is.
m (К2SO4) = n • Mr = 0.65 mol • 174.3 g / mol = 113.3 g.