Calculate the mass of the reaction product, which is formed by the interaction of 4 g of hydrogen and 160 g

Calculate the mass of the reaction product, which is formed by the interaction of 4 g of hydrogen and 160 g of bromine, if the theoretical yield of the product is 50%

1. Let’s write the reaction equation:

H2 + Br2 = 2HBr.

2. Find the chemical amount of hydrogen and bromine:

n (H2) = m (H2) / M (H2) = 4 g / 2 g / mol = 2 mol.

n (Br2) = m (Br2) / M (Br2) = 160 g / 160 g / mol = 1 mol.

3. According to the reaction equation, we find the theoretical chemical amount of hydrogen bromide, and at the end its mass:

! Bromine is in short supply.

ntheor (HBr) = n (Br2) * 2 = 1 mol * 2 = 2 mol.

nprak (HBr) = ntheor (HBr) * ω (HBr) / 100% = 2 mol * 50% / 100% = 1 mol.

m (HBr) = n (HBr) * M (HBr) = 1 mol * 81 g / mol = 81 g.

Answer: m (HBr) = 81 g.