Calculate the mass of the reaction product, which is obtained by the interaction of ethylene with a volume of 1.12 liters with a bromine mass of 1.6 g. Call this substance.
To solve, write the process equation:
H2C = CH2 + BR2 = BR – CH2 – CH2 – BR (C2H4BR) – accession, Diberomethane was formed;
M (BR2) = 159.8 g / mol;
M (C2H4BR2) = 187.8 g / mol.
1 mol of gas at n. – 22.4 l;
X mol (C2H4) – 1.12 liters from here, x mol (C2H4) = 1 * 1,12 / 22.4 = 0.05 mol (substance in excess).
We define the amount of starting material:
Y (br2) = m / m = 1.6 / 159.8 = 0.01 mol (substance in disadvantage);
Y (C2H4Br2) = 0.01 mol as the number of these substances is 1 mol.
Calculations produce by substance in a shortage.
We find a lot of product:
M (C2H4BR2) = Y * m = 0.01 * 187.8 = 1.88 g
Answer: The mass of Diberomethane is 1.88 g
One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.