Calculate the mass of the residue resulting from the interaction of an excess of barium nitrate solution

| January 5, 2021 | education

Calculate the mass of the residue resulting from the interaction of an excess of barium nitrate solution with a solution containing 7.84 g of sulfuric acid.

Barium nitrate reacts with sulfuric acid. At the same time, a water-insoluble barium sulfate salt is synthesized, which turns into an insoluble precipitate. The reaction is described by the following chemical reaction equation.
Ba (NO3) 2 + H2SO4 = BaSO4 + 2HNO3;
Barium nitrate reacts with sulfuric acid in equal molar amounts. This synthesizes the same amount of insoluble barium sulfate.
Let’s determine the chemical amount of sulfuric acid.
M H2SO4 = 2 + 32 + 16 x 4 = 98 grams / mol; N H2SO4 = 7.84 / 98 = 0.08 mol;
The same amount of sulfuric acid will be used.
Barium sulfate will be obtained in the same molar amount.
Let’s calculate its weight.
M BaSO4 = 137 + 32 + 16 x 4 = 233 grams / mol; m BaSO4 = 0.08 x 233 = 18.64 grams



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