Calculate the mass of the resulting oxide if magnesium interacts a mass of 150 grams containing

Calculate the mass of the resulting oxide if magnesium interacts a mass of 150 grams containing 29 percent of oxygen impurities with an oxygen volume of 44 liters.

Metal magnesium reacts intensively with oxygen. The reaction is described by the following chemical reaction equation:

Mg + ½ O2 = MGO;

When oxidizing to the magnesium atom, one oxygen atom is connected. At the same time, one magnesium oxide molecule is synthesized.

We define the chemical (molar) amount of magnesium.

To do this, share the existing weight of magnesium on weight 1 praying this substance.

M mg = 24 grams / mole; N mg = 150 x 0.71 / 24 = 4,4375 mol;

Calculate the molar amount of oxygen.

N O2 = 44 / 22.4 = 1.964 mol;

We have a lack of oxygen. In the course of the reaction, 1,964 x 2 = 3.928 mol of magnesium will be oxidized.

The same amount of oxide will be synthesized.

We calculate its weight.

Multiply the amount of substance on the weight of 1 praying substance.

M MgO = 24 + 16 = 40 grams / mole; m MgO = 3.928 x 40 = 157.12 grams;