Calculate the mass of the salt formed as a result of the interaction of 48 g of 20% sulfuric acid solution and barium chloride.

H2SO4 + BaCl2 = 2HCl + BaSO4.

Mr (H2SO4) = 98 g / mol, Mr (BaSO4) = 233 g / mol. The reaction shows that from 98 g of sulfuric acid, 233 g of barium sulfate are formed. Let’s find what mass of sulfuric acid is contained in a 20% solution:

w = 20% = m (acid) / m (solution) * 100% = x / 48 * 100%. Hence x = 9.6 g.

Now let’s make a proportion to find the desired mass of barium sulfate, formed from 48 g of a 20% acid solution:

9.6 g – y g

98 g – 233 g

We get that y = 9.6 * 233/98 = 22.8 g.