Calculate the mass of the salt formed as a result of the interaction of barium hydroxide with a mass

| February 16, 2021 | education

Calculate the mass of the salt formed as a result of the interaction of barium hydroxide with a mass of 51.3 and sulfur (4) oxide with a volume of 4.48 liters.

1. Let’s write down the equality of chemical interaction:

Ba (OH) 2 + SO2 = BaSO3 + H2O.

2. Calculate the number of moles of barium hydroxide and sulfur dioxide (Vm – molar volume, constant equal to 22.4 l / mol):

n (Ba (OH) 2) = m (Ba (OH) 2) / M (Ba (OH) 2) = 51.3 g / 171 g / mol = 0.3 mol.

n (SO2) = V (SO2) / Vm = 4.48 L / 22.4 L / mol = 0.2 mol.

3. Using the equality of the chemical interaction, we calculate the number of moles and the mass of barium sulfite:

! SO2 is in short supply.

n (BaSO3) = n (SO2) = 0.2 mol.

m (BaSO3) = n (BaSO3) * M (BaSO3) = 0.2 mol * 217 g / mol = 43.4 g.

Result: m (BaSO3) = 43.4 g.



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