Calculate the mass of the salt formed by the interaction of 16 kg of sodium hydroxide in an excess of sulfuric acid.

2NaOH + H2SO4 = Na2SO2 + 2H20
Let’s find the amount of substance (NaOH) by the formula: n = m / M, where n is the amount of the substance, m is the mass of the substance, M is the molar mass of the substance.
Let’s translate kg. in grams
16 kg = 16000 g
M (NaOH) = 23 + 16 + 1 = 40 g / mol
n (NaOH) = 16000/40 = 400 mol
According to the reaction equation, we see that n (Na2SO4) is 2 times less than n (NaOH)
n (Na2SO4) = n (NaOH) / 2
n (Na2SO4) = 400/2 = 200 mol
Find the mass by the formula m = M × n
M (Na2SO4) = 23 × 2 + 32 + 16 × 4 = 142 g / mol
m (Na2SO4) = 142 × 200 = 28400 g
Let’s convert to kg
m (Na2SO4) = 28.4 kg
Answer: mass of Na2SO4 = 28.4 kg