Calculate the mass of the salt formed by the interaction of 2 mol of iron and 2 mol of copper sulfate (2);

Given:
n (Fe) = 2 mol
n (CuSO4) = 2 mol

Find:
m (salt) -?

Solution:
1) Fe + CuSO4 => FeSO4 + Cu;
2) n (FeSO4) = n (Fe) = n (CuSO4) = 2 mol;
3) m (FeSO4) = n (FeSO4) * M (FeSO4) = 2 * 152 = 304 g.

Answer: The mass of FeSO4 is 304 g.



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