Calculate the mass of the salt formed by the interaction of 20 g of copper oxide II with nitric acid.

CuO + 2HNO3 = Cu (NO3) 2 + H2O.
1) Find the molar mass of copper oxide. To do this, we will use the periodic table: 64 + 16 = 80.
2) Find the amount of copper oxide substance. To do this, divide the mass by the molar mass: 20/80 = 0.25 mol.
3) According to the reaction equation, one mole of oxide is one mole of copper nitrate. This means that the amount of copper nitrate substance is 0.25 mol.
4) The molar mass of copper nitrate is: 64 + 28 + 96 = 188.
5) Mass of copper nitrate: 0.25 * 188 = 47g – the answer.

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