Calculate the mass of the salt formed by the interaction of 200 g of 10% sodium hydroxide solution with 7.3 g of hydrochloric acid.
1. Let’s compose the equation of the chemical reaction:
NaOH + HCl = NaCl + H2O.
2. Find the chemical amount of sodium hydroxide and hydrochloric acid:
m (NaOH) = m (solution) * ω (NaOH) / 100% = 200 g * 10% / 100% = 20 g.
n (NaOH) = m (NaOH) / M (NaOH) = 20 g / 40 g / mol = 0.5 mol.
n (HCl) = m (HCl) / M (HCl) = 7.3 g / 36.5 g / mol = 0.2 mol.
3. According to the reaction equation, we find the chemical amount, and then the mass of sodium chloride:
! HCl is in short supply.
n (NaCl) = n (HCl) = 0.2 mol.
m (NaCl) = n (NaCl) * M (NaCl) = 0.2 mol * 58.5 g / mol = 11.7 g.
Answer: m (NaCl) = 11.7 g.
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