# Calculate the mass of the salt formed by the interaction of 200 g of 10% sodium hydroxide

Calculate the mass of the salt formed by the interaction of 200 g of 10% sodium hydroxide solution with 7.3 g of hydrochloric acid.

1. Let’s compose the equation of the chemical reaction:

NaOH + HCl = NaCl + H2O.

2. Find the chemical amount of sodium hydroxide and hydrochloric acid:

m (NaOH) = m (solution) * ω (NaOH) / 100% = 200 g * 10% / 100% = 20 g.

n (NaOH) = m (NaOH) / M (NaOH) = 20 g / 40 g / mol = 0.5 mol.

n (HCl) = m (HCl) / M (HCl) = 7.3 g / 36.5 g / mol = 0.2 mol.

3. According to the reaction equation, we find the chemical amount, and then the mass of sodium chloride:

! HCl is in short supply.

n (NaCl) = n (HCl) = 0.2 mol.

m (NaCl) = n (NaCl) * M (NaCl) = 0.2 mol * 58.5 g / mol = 11.7 g.

Answer: m (NaCl) = 11.7 g.

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