Calculate the mass of the salt formed by the interaction of 200 g of a 15% nitric acid

Calculate the mass of the salt formed by the interaction of 200 g of a 15% nitric acid solution with a sufficient amount of calcium oxide.

1. Let’s compose the reaction equation:

CaO + 2HNO3 = Ca (NO3) 2 + H2O;

2. find the mass of nitric acid:

m (HNO3) = w (HNO3) * m (solution) = 0.15 * 200 = 30 g;

3.Calculate the chemical amount of the reacting acid:

n (HNO3) = m (HNO3): M (HNO3);

M (HNO3) = 1 + 14 + 3 * 16 = 63 g / mol;

n (HNO3) = 30: 63 = 0.4762 mol;

4.determine the amount of calcium nitrate and calculate its mass:

n (Ca (NO3) 2) = n (HNO3): 2 = 0.4762: 2 = 0.2381 mol;

m (Ca (NO3) 2) = n (Ca (NO3) 2) * M (Ca (NO3) 2);

M (Ca (NO3) 2) = 40 + 2 * 14 + 6 * 16 = 164 g / mol;

m (Ca (NO3) 2) = 0.2381 * 164 = 39.05 g.

Answer: 39.05 g.