Calculate the mass of the salt formed by the interaction of 490 g of a 12% sulfuric acid solution with aluminum.

1. Knowing the mass fraction of sulfuric acid in the solution and the mass of the solution, you can calculate the mass of sulfuric acid.

w = m (substance): m (solution) x 100%.

m (acid) = 58.8 g.

2. Let’s calculate the amount of sulfuric acid substance.

n = m: M, M (acid) = 1 x 2 + 32 + 16 x 4 = 98g / mol.

n = 58.8 g: 98 g / mol = 0.6 mol.

3. We make the equation of the reaction between sulfuric acid and aluminum.

According to the reaction equation, we determine in what proportions are sulfuric acid and the resulting salt – aluminum sulfate.

Sulfuric acid is 3 mol, and salt is 1 mol, that is, the acid is 3 times more, therefore, the amount of substance is 3 times more than that of salt.

n (salt) = 0.6 mol: 3 = 0.2 mol.

4. Knowing the amount of the salt substance, now we can calculate the salt mass by the formula.

Answer: m (salt) = 68.4 g.