Calculate the mass of the salt formed by the interaction of 6 liters. carbon dioxide containing 4%

Calculate the mass of the salt formed by the interaction of 6 liters. carbon dioxide containing 4% impurities with calcium oxide.

First, let’s calculate the mass of pure carbon dioxide that has reacted:
CaO + CO2 = CaCO3
To do this, we first find the volume of pure carbon dioxide:
V (CO2) = V (total gas) * percentage concentration = 6 * 0.96 = 5.76 liters.
where percentage concentration = 100% – 4% (impurities) = 96% or 0.96
The molar volume of any gas under normal conditions is 22.4 l / mol
Let’s calculate the molar mass of the salt – calcium carbonate, obtained during the reaction:
M (salt) = M (Ca) + M (C) + 2 * M (O) = 40 + 12 + 2 * 16 = 84 g / mol
Based on this, we will make the proportion:
5.76 / 22.4 = x / 84
where x is the desired mass of salt obtained during the reaction
x = 5.76 * 84/22, 4 = 21.6 g.
Answer: The mass of calcium carbonate is 21.6 g.