Calculate the mass of the salt formed by the interaction of a solution of sulfuric acid weighing 196 g

| January 10, 2021 | education

Calculate the mass of the salt formed by the interaction of a solution of sulfuric acid weighing 196 g with a mass fraction of 10% with aluminum.

3H2SO4 + 2Al = Al2 (SO4) 3 + 3H2.
1) Find the mass of the solute of sulfuric acid in its solution. For this, we multiply the mass fraction of the substance by the mass of the solution and divide by one hundred percent: 196 * 10/100 = 19.6 g.
2) Molar mass of sulfuric acid: 2 + 32 + 64 = 98.
3) The amount of sulfuric acid substance: 19.6 / 98 = 0.2 mol.
4) According to the reaction equation, there is one mole of aluminum sulfate for three moles of sulfuric acid. This means that the amount of aluminum sulfate substance is: 3 * 0.2 = 0.6 mol.
5) Mass of aluminum sulfate: 0.6 * (2 * 27 + 3 (32 + 64)) = 0.6 * 342 = 205.2 g – answer.



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