Calculate the mass of the salt formed by the reaction of 0.2 mol of calcium orthophosphate

Calculate the mass of the salt formed by the reaction of 0.2 mol of calcium orthophosphate per 19.6 g of phosphoric acid.

Let us write the reaction equation for the interaction of phosphoric acid and calcium orthophosphate:

Ca3 (PO4) 2 + 4H3PO4 => 3Ca (H2PO4) 2.

Find the number of moles of acid:

n (H3PO4) = m / Mr = 19.6 / 98 = 0.2 mol.

Theoretically, the number of moles of starting materials will be 1: 1, and from the equation 1: 4. Therefore, the calculation is carried out by a disadvantage.

Mass of calcium orthophosphate :.

m (Ca3 (PO4) 2) = n • Mr = 0.2 • 278 = 55.6 g.

If from 55.6 g of orthophosphate x g of salt is formed, then from 278 g – 202 g.

x = 55.6 * 202/278 = 40.4.

We get m (Ca (H2PO4) 2) = 40.4 g.