Calculate the mass of the salt formed by the reaction of 10 g of sodium carbonate and 20 g of hydrochloric acid.

1. Let’s compose the equation of the chemical reaction:

Na2CO3 + 2HCl = 2NaCl + CO2 + H2O.

2. Find the chemical amount of sodium carbonate and hydrochloric acid that have reacted:

n (Na2CO3) = m (Na2CO3) / M (Na2CO3) = 10 g / 106 g / mol = 0.094 mol.

n (HCl) = m (HCl) / M (HCl) = 20 g / 36.5 g / mol = 0.55 mol.

3. According to the reaction equation, we find the chemical amount, and then the mass of sodium chloride:

! Na2CO3 is in short supply.

n (NaCl) = n (Na2CO3) * 2 = 0.19 mol.

m (NaCl) = n (NaCl) * M (NaCl) = 0.19 mol * 58.5 g / mol = 11.04 g.

Answer: m (NaCl) = 11.04 g.