Calculate the mass of the salt formed by the reaction of 200 g, 10% solution of nitric acid, Mg hydroxide.

1. Let’s compose the equation of the chemical reaction:

2HNO3 + Mg (OH) 2 = Mg (NO3) 2 + 2H2O.

2. Find the chemical amount of nitric acid:

m (HNO3) = m (solution) * ω (HNO3) / 100% = 200 g * 10% / 100% = 20 g.

n (HNO3) = m (HNO3) / M (HNO3) = 20 g / 63 g / mol = 0.317 mol.

3. According to the reaction equation, we find the chemical amount, and then the mass of magnesium nitrate:

n (Mg (NO3) 2) = n (HNO3) / 2 = 0.317 mol / 2 = 0.159 mol.

m (Mg (NO3) 2) = n (Mg (NO3) 2) * M (Mg (NO3) 2) = 0.159 mol * 148 g / mol = 23.5 g.

Answer: m (Mg (NO3) 2) = 23.5 g.