Calculate the mass of the salt formed by the reaction of 200 g of nitric acid with a sufficient amount of copper oxide.

Given:

m (HNO3) = 200 g

Find:

m (salt) -?

Solution:

1) We compose the reaction equation corresponding to the condition of the problem:

2HNO3 + CuO = Cu (NO3) 2 + H2O;

2) Find the amount of nitric acid contained in 200 grams of the substance:

n (HNO3) = m: M = 200 g: 63 g / mol = 3.17 mol;

3) We compose logical equality:

if 2 mol of HNO3 gives 1 mol of Cu (NO3) 2,

then 3.17 mol HNO3 will give x mol Cu (NO3) 2,

then x = 1.585 mol.

4) Find the mass of copper nitrate formed as a result of the reaction:

m (Cu (NO3) 2) = n * M = 1.585 mol * 188 g / mol = 297.98 g.

Answer: m (Cu (NO3) 2) = 297.98 g.