Calculate the mass of the salt formed during the reaction of magnesium with sulfuric acid

Calculate the mass of the salt formed during the reaction of magnesium with sulfuric acid, if hydrogen was released in the volume of 12 dm³? Name the resulting salt.

If magnesium is added to hydrochloric acid, then an intense chemical reaction begins with the release of gaseous hydrogen and the formation of a salt of magnesium chloride:

Mg + H2SO4 = MgSO4 + H2;

In accordance with the coefficients of the equation, when 1 mol of magnesium is dissolved, 1 mol of gaseous hydrogen is released.

Let’s calculate the chemical amount of hydrogen, for this we divide its volume by the volume of 1 mole of gas (22.4 liters).

N H2 = 1.2 x 22.4 = 0.054 liters;

The same amount of magnesium sulfate will be synthesized.

Calculate the weight of 0.054 mol of magnesium sulfate.

M MgSO4 = 24 + 32 + 16 x 4 = 120 grams / mol;

m MgSO4 = 0.054 x 120 = 6.48 grams;



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