Calculate the mass of the salt formed if 14g has reacted with the acid. sodium hydroxide

Given:
m (NaOH) = 14 g
To find:
m (NaCl)
Decision:
NaOH + HCl = NaCl + H2O
n (NaOH) = m / M = 14 g / 40 g / mol = 0.35 mol
n (NaOH): n (NaCl) = 1: 1
n (NaCl) = 0.35 mol
m (NaCl) = n * M = 0.35 mol * 58.5 g / mol = 20.48 g
Answer: 20.48 g



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