# Calculate the mass of the salt formed when draining 200 g of 10% hydrochloric

Calculate the mass of the salt formed when draining 200 g of 10% hydrochloric acid solution and 200 g of 20% potassium hydroxide solution.

1. Let’s compose the equation of the chemical reaction:

KOH + HCl = KCl + H2O.

2. Find the chemical amount of potassium hydroxide and hydrochloric acid:

m (KOH) = m (solution) * ω (KOH) / 100% = 200 g * 20% / 100% = 40 g.

n (KOH) = m (KOH) / M (KOH) = 40 g / 56 g / mol = 0.71 mol.

m (HCl) = m (solution) * ω (HCl) / 100% = 200 g * 10% / 100% = 20 g.

n (HCl) = m (HCl) / M (HCl) = 20 g / 36.5 g / mol = 0.55 mol.

3. Find the chemical amount, and then the mass of potassium chloride:

! HCl is in short supply.

n (KCl) = n (HCl) = 0.55 mol.

m (KCl) = n (KCl) * M (KCl) = 0.55 mol * 74.5 g / mol = 40.82 g.

Answer: m (KCl) = 40.82 g.

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