Calculate the mass of the salt obtained by reacting 100 g of a 25% sulfuric acid solution with an excess of copper (II) oxide

H2SO4 + CuO = CuSO4 + H2O
Sulfuric acid mass: 100 g * 25% / 100% = 25 g. This amounts to: 25 g / 98 g / mol = 0.255 mol.

Knowing the molar mass of copper sulfate, you can calculate its mass:

160 g / mol * 0.255 mol = 40.8 g.



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