Calculate the mass of the salt obtained by reacting 108 g of a 14% nitric acid solution with 32.21 g of barium oxide containing

Calculate the mass of the salt obtained by reacting 108 g of a 14% nitric acid solution with 32.21 g of barium oxide containing 5% impurities if the reaction product yield is 80%.

BaO + 2HNO3 = Ba (NO3) 2 + H2O
m HNO3 = 108 * 0.14 = 15.12 g
n HNO3 = 15.12 / 63 = 0.24 mol
m BaO = 32.21 * 0.95 = 30.5995 g
n BaO = 30.5995 / 153.33 = 0.2 mol
n Ba (NO3) 2 = 0.12 mol
m Ba (NO3) 2 = 0.12 * 398.66 = 47.84 g



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