Calculate the mass of the salt obtained by reacting 8 g of magnesium oxide with an excess of sulfuric acid.

Let’s write the reaction equation:

MgO + H2SO4 = MgSO4 + H2O

Let’s find the amount of magnesium oxide substance:

v (MgO) = m (MgO) / M (MgO) = 8/40 = 0.2 (mol).

According to the reaction equation, 1 mol of MgSO4 is formed per 1 mol of MgO, therefore:

v (MgSO4) = v (MgO) = 0.2 (mol).

Thus, the mass of the obtained magnesium sulfate salt:

m (MgSO4) = v (MgSO4) * M (MgSO4) = 0.2 * 120 = 24 (g).

Answer: 24 g.