Calculate the mass of the salt obtained by the interaction of 4.8 g of magnesium and 3.2 g of sulfur.

1. Let’s compose the equation of chemical reactions:

Mg + S = MgS.

2. Let’s find the chemical amount of magnesium and sulfur that have entered into the reaction:

n (Mg) = m (Mg) / M (Mg) = 4.8 g / 24 g / mol = 0.2 mol.

n (S) = m (S) / M (S) = 3.2 g / 32 g / mol = 0.1 mol.

3. According to the reaction equation, we find the chemical amount, and then the mass of magnesium sulfide:

! S is at a disadvantage.

n (MgS) = n (S) = 0.1 mol.

m (MgS) = n (MgS) * M (MgS) = 0.1 mol * 56 g / mol = 5.6 g.

Answer: m (MgS) = 5.6 g.