Calculate the mass of the salt that forms when aluminum reacts with 2.4 mol of sulfur.

n (S) = 2.4 mol.
2Al + 3S => Al2S3 n (Al2S3) = n (S) /3=2.4/3=0.8 mol.
m (Al2S3) = n * M = 0.8 mol * 150 g / mol = 120 g.
Answer: m (Al2S3) = 120g.



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