Calculate the mass of the salt that is formed as a result of the interaction of a 20% formic acid solution weighing

Calculate the mass of the salt that is formed as a result of the interaction of a 20% formic acid solution weighing 57.5 g and a 10% potassium hydroxide solution weighing 112 g.

Given:
ω (HCOOH) = 20%
m solution (HCOOH) = 57.5 g
ω (KOH) = 10%
m solution (KOH) = 112 g

To find:
m (salt) -?

1) HCOOH + KOH => HCOOK + H2O;
2) m (HCOOH) = ω * m / 100% = 20% * 57.5 / 100% = 11.5 g;
3) M (HCOOH) = 46 g / mol;
4) n (HCOOH) = m / M = 11.5 / 46 = 0.25 mol;
5) m (KOH) = ω * m / 100% = 10% * 112/100% = 11.2 g;
6) M (KOH) = 56 g / mol;
7) n (KOH) = m / M = 11.2 / 56 = 0.2 mol;
8) n (HCOOK) = n (KOH) = 0.2 mol;
9) M (HCOOK) = 84 g / mol;
10) m (HCOOK) = n * M = 0.2 * 84 = 16.8 g.

Answer: HCOOK mass is 16.8 g.