Calculate the mass of the salt that is formed by the interaction of 14 g of 20% HCl solution with KOH.

Given:

m (HCl) = 14 g

w% (HCl) = 20%

To find:

m (salt) -?

Decision:

1) We compose the reaction equation according to the condition of the problem:

HCl + KOH = KCl + H2O;

2) Find the mass of hydrochloric acid in the solution:

m (HCl) = 14 g * 0.2 = 2.8 g;

3) Find the amount of acid:

n (HCl) = m: M = 2.8 g: 36.5 g / mol = 0.0767 mol;

4) We compose a logical expression:

if 1 mol of HCl gives 1 mol of KCl,

then 0.0767 mol HCl will give x mol KCl,

then x = 0.0767 mol.

5) Find the mass of potassium chloride formed as a result of the reaction:

m (KCl) = n * M = 0.0767 mol * 74.5 g / mol = 5.7 g;

Answer: m (KCl) = 5.7 g.