Calculate the mass of the salt that is formed by the interaction of 2.7 g of aluminum with hydrochloric acid.

1. Let’s compose the equation for the reaction of aluminum with hydrochloric acid:

2Al + 6HCl = 2AlCl3 + 3H2 ↑;

2. find the chemical amount of aluminum:

n (Al) = m (Al); M (Al) = 2.7: 27 = 0.1 mol;

3.According to the recording of the reaction equation, the amount of salt obtained will coincide with the amount of reacted aluminum:

n (AlCl3) = n (Al) = 0.1 mol;

4.Calculate the mass of the obtained aluminum chloride:

m (AlCl3) = n (AlCl3) * M (AlCl3);

M (AlCl3) = 27 + 3 * 35.5 = 133.5 g / mol;

m (AlCl3) = 0.1 * 133.5 = 13.35 g.

Answer: 13.35 g.