Calculate the mass of the salt that is formed by the interaction of 200 g of 10% sodium hydroxide solution with hydrochloric acid solution.
1.Let’s find the mass of NaOH in the solution.
W = m (substance): m (solution) × 100%, hence
m (substance) = (m (solution) × W): 100%.
m (substance) = (200 g × 10%): 100% = 20 g.
2.Let’s find the amount of NaOH.
M (NaOH) = 40 g / mol.
n = 20 g: 40 g / mol = 0.5 mol.
Let’s find the quantitative ratios of substances.
HCl + NaOH = NaCl + H2O.
For 1 mole of NaOH, there is 1 mole of NaCl.
The substances are in quantitative ratios of 1: 1.
The amount of substance is equal.
n (NaCl) = n (NaOH) = 0.5 mol.
3. Find the mass of NaCl.
m = nM.
М (NaCl) = 58.5 g / mol.
m = 0.5 mol × 58.5 g / mol = 29.25 g.
Answer: 29.25 g.
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