Calculate the mass of the salt that is formed by the interaction of 200 g of 10% sodium hydroxide

Calculate the mass of the salt that is formed by the interaction of 200 g of 10% sodium hydroxide solution with hydrochloric acid solution.

1.Let’s find the mass of NaOH in the solution.

W = m (substance): m (solution) × 100%, hence

m (substance) = (m (solution) × W): 100%.

m (substance) = (200 g × 10%): 100% = 20 g.

2.Let’s find the amount of NaOH.

M (NaOH) = 40 g / mol.

n = 20 g: 40 g / mol = 0.5 mol.

Let’s find the quantitative ratios of substances.

HCl + NaOH = NaCl + H2O.

For 1 mole of NaOH, there is 1 mole of NaCl.

The substances are in quantitative ratios of 1: 1.

The amount of substance is equal.

n (NaCl) = n (NaOH) = 0.5 mol.

3. Find the mass of NaCl.

m = nM.

М (NaCl) = 58.5 g / mol.

m = 0.5 mol × 58.5 g / mol = 29.25 g.

Answer: 29.25 g.