Calculate the mass of the salt that is formed by the interaction of 30 g of aminoacetic acid with 250 g

Calculate the mass of the salt that is formed by the interaction of 30 g of aminoacetic acid with 250 g of a 10% sulfuric acid solution?

Given:
m (NH2-CH2-COOH) = 30 g
m solution (H2SO4) = 250 g
ω (H2SO4) = 10%

To find:
m (salt) -?

1) 2NH2-CH2-COOH + H2SO4 => (NH3-CH2-COOH) 2SO4;
2) M (NH2-CH2-COOH) = 75 g / mol;
3) n (NH2-CH2-COOH) = m / M = 30/75 = 0.4 mol;
4) m (H2SO4) = ω * m solution / 100% = 10% * 250/100% = 25 g;
5) n (H2SO4) = m / M = 25/98 = 0.26 mol;
6) n ((NH3-CH2-COOH) 2SO4) = n (NH2-CH2-COOH) / 2 = 0.4 / 2 = 0.2 mol;
7) M ((NH3-CH2-COOH) 2SO4) = 248 g / mol;
8) m ((NH3-CH2-COOH) 2SO4) = n * M = 0.2 * 248 = 49.6 g.

Answer: The mass of (NH3-CH2-COOH) 2SO4 is 49.6 g.