Calculate the mass of the salt that is formed by the interaction of 49 g of sulfuric acid and 20 g of sodium hydroxide.

The reaction of sulfuric acid and sodium hydroxide is described by the following chemical reaction equation.

2NaOH + H2SO4 = Na2SO4 + 2H2O;

Two moles of alkali react with one mole of acid to form one mole of salt.

Let’s determine the available quantities of the substance.

M H2SO4 = 2 + 32 + 16 x 4 = 98 grams / mol;

N H2SO4 = 49/98 = 0.5 mol;

M NaOH = 23 + 16 + 1 = 40 grams / mol;

N NaOH = 20/40 = 0.5 mol;

During the reaction of 0.5 mol of alkali with 0.25 mol of acid, 0.25 mol of salt is formed.

Let’s find its mass.

M Na2SO4 = 23 x 2 + 32 + 16 x 4 = 142 grams / mol;

m Na2SO4 = 142 x 0.25 = 35.5 grams;