Calculate the mass of the salt that is formed by the interaction of 9.8 g of sulfuric acid and 50 g of barium chloride.

The reaction between sulfuric acid and barium chloride is described by the following chemical reaction equation:

BaCl2 + H2SO4 = BaSO4 + 2HCl;

In the interaction of 1 mol of barium chloride and 1 mol of sulfuric acid, 1 mol of insoluble barium sulfate is synthesized.

Let’s calculate the chemical amount of a substance that is contained in 50 grams of barium chloride.

M BaCl2 = 137 + 35.5 x 2 = 208 grams / mol;

N BaCl2 = 50/208 = 0.24 mol;

Let’s calculate the chemical amount of a substance that is contained in 9.8 grams of sulfuric acid.

M H2SO4 = 2 + 32 + 16 x 4 = 98 grams / mol;

N H2SO4 = 9.8 / 98 = 0.1 mol;

Thus, no more than 0.24 mol of barium sulfate will be synthesized.

Let’s calculate its weight.

M BaSO4 = 137 + 32 + 16 x 4 = 233 grams / mol;

m BaSO4 = 233 x 0.24 = 55.92 grams;