Calculate the mass of the salt that is formed in the solution after the interaction of 20 g of a 25.2%

Calculate the mass of the salt that is formed in the solution after the interaction of 20 g of a 25.2% nitric acid solution with an insoluble base.

Given:
m solution (HNO3) = 20 g
ω (HNO3) = 25.2%

To find:
m (salt) -?

Decision:
1) Zn (OH) 2 + 2HNO3 => Zn (NO3) 2 + 2H2O;
2) m (HNO3) = ω (HNO3) * m solution (HNO3) / 100% = 25.2% * 20/100% = 5.04 g;
3) n (HNO3) = m (HNO3) / Mr (HNO3) = 5.04 / 63 = 0.08 mol;
4) n (Zn (NO3) 2) = n (HNO3) / 2 = 0.08 / 2 = 0.04 mol;
5) m (Zn (NO3) 2) = n (Zn (NO3) 2) * Mr (Zn (NO3) 2) = 0.04 * 189 = 7.56 g.

Answer: The mass of Zn (NO3) 2 is 7.56 g.



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