Calculate the mass of the salt that was formed by the interaction of 280 g of hydrochloric acid with magnesium hydroxide

univerkov | January 17, 2021 | education

Given:
m (HCl) = 280 g
To find:
m (MgCl2)
Decision:
Mg (OH) 2 + 2HCl = MgCl2 + 2H2O
n (HCl) = m / M = 280 g / 36.5 g / mol = 7.67 mol
n (HCl): n (MgCl2) = 2: 1
n (MgCl2) = 3.84 mol
m (MgCl2) = n * M = 3.84 mol * 95 g / mol = 364.8 g
Answer: 364.8 g

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