Calculate the mass of the sediment obtained by mixing 250 grams of an 8% solution of ferrous sulfate

Calculate the mass of the sediment obtained by mixing 250 grams of an 8% solution of ferrous sulfate (||) and 250 grams of an 8% solution of barium nitrate.

1.n (FeSO4) = 250 * 0.08 / 152 = 0.132 mol
n (Ba (NO3) 2) = 250 * 0.08 / 261 = 0.077 mol
2.FeSO4 + Ba (NO3) 2 = BaSO4 + Fe (NO3) 2
Ba (NO3) 2 – deficient, n (BaSO4) = n (Ba (NO3) 2) = 0.077 mol
m (BaSO4) = 0.077 * 233 = 17.941 g



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